alasnya itu(M+4) tinggi(2m-8) kelilingnya 88

diketahui:
alas = m+4
kaki = 2m-8
K = 88

ditanya:
AC = 2m-8

dijawab:
K = 2×kaki + alas
88 = 2(2m-8) + m+4
88 = 4m-16+m+4
88 = 5m-12
5m = 100
m = 20

AC = 2m-8
AC = 2(20)-8
AC = 40-8
AC = 32 (D)

karena itu segitiga sama kaki, berarti AC = CB 

keliling = sisi 1 + sisi 2 + sisi 3
88 = 2(2m-8) + (m+4)
88= 4m - 16 + m + 4
88 = 5m - 12
100 = 5m
m = 20


CB = AC = (2m-8)
AC = 40 - 8 = 32