panjang oa = 10cm , of = 6cm , maka panjang tali busur bc adalah ...

Segitiga siku2 jadi pakai phitagoras
OA jari2 sehingga OA=OC =10 cm
FC^2= OC^2 - OF^2
FC^2= 10^2 - 6^2
FC^2= 100 - 36
FC^2= 64
FC = akar 64
FC = 8cm

Tali busur = CB =CF+FB = 8+8 =16 cm