????????????????kimia

n ch3cooh = MxV=1x100=100mmol
n ch3coona=MxV=1x100=100mmol
n hcl = MxV= 1x5=5mmol

merupakan penyangga asam karena diketahui sam lemah dan garamnya
[h+] = Ka x nch3cooh+nhcl/nch3coona-nhcl
       = 1,8x10^-5 x  100+5/100-5
       = 1,8x10^-5 x  105/95
       =1,98x10^-5
       = 2x10^-5
ph = -log[h+]
     = -log 2x10^-5
     = 5-log2
semoga membantu :)