x^2+4y^2=12xy nilai log(x+2y)^2/(x-2y)^2 adalahh..... tolong di bantu yaaa butuh sekarangg

x² + 4y² = 12xy

log (x + 2y)² / (x - 2y)²
= log (x² + 4xy + 4y²) / (x² - 4xy + 4y²)
= log (12xy + 4xy) / (12xy - 4xy)
= log 16xy / 8xy
= log 2

[tex]log \frac{ (x+2y)^2}{(x-2y)^2} \\ \\= log \frac{x^2+4y^2+4xy}{x^2+4y^2-4xy} \\ \\= log \frac{12xy+4xy}{12xy-4xy} \\ \\= log \frac{16xy}{8xy} \\ \\= log2 [/tex]