asam phospat 0,1 M mempunyai pH = 2 - log 3. tentukan derajat ionisasi asam phospat?

H3PO4 → 3H+ + PO4^3-

pH = 2 - log3
-log[H+] = 2 - log3
[H+] = 3 x 10^-2

→ Derajat Ionisasi :
= [H+] / [H3PO4]
= 3 x 10^-2 / 10^-1
= 3 x 10^-1
= 0,3