integral sin^2xcos^2xdx

[tex]\int \:sin^2xcos^2xdx \\ \\ =\int \frac{1-\cos \left(4x\right)}{8}dx \\ \\ = \frac{1}{8} \int (1-cos(4x)dx \\ \\ = \frac{1}{8}(x- \frac{1}{4}sin(2x))+c [/tex]