diketahui f' (x) = 3x^2 + 4x-3 dab F (2) = -8. Fungsi F (x) adalah ....

INTEGRAL

f(x) = integral f'(x)
f(x) = x^3 + 2x^2 - 3x + C
f(2) = 2^3 + 2×2^2 - 3×2 + C
-8 = 8 + 8 - 6 + C
-8 = 10 + C
C = -8-10
C = -18

jadi
f(x) = x^3 + 2x^2 - 3x - 18