jika segitiga AFD=segitiga BEC dangan AF=3 cm,FE=8 cm,dan AD=5 cm,maka tentukan luas dan keliling trapesium!!

DF = 4 cm
L = ( 8 + 14 ) x 4 : 2 = 44 cm*2

Kll= 5+14+5+8 = 32 cm

t trapesium = DF
DF = AD^2 - AF^2
= 5^2 - 3^2
= 25 - 9
= √16
= 4 cm
sisi atas = DC = FE = 8 cm
sisi bawah = AB
AB = AF × 2 + FE = 3×2+8 = 6+8 = 14 cm
L trapesium
= 1/2 × (sisi atas + sisi bawah) × t
= 1/2 × ( DC + AB ) × DF
= 1/2 × ( 8cm + 14cm ) × 4cm
= 1/2 × 22cm × 4 cm
= 11cm × 4cm
= 44 cm^2
K trapesium = s1 + s2 + s3 +s4
= AD + DC + CB + BE
= 5cm + 8cm + 5cm + 14cm
= 32cm