Matematika

Pertanyaan

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1 Jawaban

  • 3.
    BC/sin 30 = AB/sin C
    12 / 1/2 = 12 akar 3 / sin C
    sin C = 1/2 akar 3
    C = 60°

    sudut B = 180 - 60 - 30 = 90°

    AC^2 = AB^2 + BC^2
    AC^2 = (12 akar3)^2 + 12^2
    AC^2 = 432 + 144 = 576
    AC = 24 cm

    4.
    tan 60 = akar 3
    CD/4 = akar 3
    CD = 4 akar 3 cm

    BD cos60 = 4
    BD . 1/2 = 4
    BD = 8 cm

    tan 30 = 1/3 akar 3
    4 akar 3 / AC = 1/3 akar 3
    AC = 12 cm

    AB = 12 - 4 = 8 cm