A= (1 2) (1 3) B= (3 2) (2 2) (AB) -¹ ????
Matematika
parlinsianipar
Pertanyaan
A=
(1 2)
(1 3)
B=
(3 2)
(2 2)
(AB) -¹ ????
(1 2)
(1 3)
B=
(3 2)
(2 2)
(AB) -¹ ????
1 Jawaban
-
1. Jawaban vera
[tex]AB= \left[\begin{array}{ccc}1&2\\1&3\\\end {array}\right] \left[\begin{array}{ccc}3&2\\2&2\end{array}\right]
AB= \left[\begin{array}{ccc}1.3+2.2&1.2+2.2\\1.3+3.2&1.2+3.2\\\end{array}\right]
AB= \left[\begin{array}{ccc}7&6\\9&8\\\end{array}\right] AB^{-1} = \frac{1}{det.AB} [Adjoin~AB]
AB^{-1} = \frac{1}{7.8~-~6.9} \left[\begin{array}{ccc}8&-6\\-9&7\\\end{array}\right]
AB^{-1} = \frac{1}{2} \left[\begin{array}{ccc}8&-6\\-9&7\\\end{array}\right] [/tex]
[tex]
AB^{-1} = \left[\begin{array}{ccc}4&-3\\- \frac{9}{2} & \frac{7}{2} \\\end{array}\right] [/tex]