diberikan kosentrasi H2SO4 0,02M. konsentrasi OH^- adalah...

semoga bisa membantu ya

H2SO4 → 2H+ + SO4^2-

[H+] = valensi . [H2SO4]
[H+] = 2 . 0,02
[H+] = 0,04
[H+] = 4 x 10^-2

pH = -log[H+]
pH = -log 4 x 10^-2
pH = 2 - log4

pOH = 14 - (2 - log4)
pOH = 14 - 2 + log4
pOH = 12 + log4

pOH = -log [OH-]
12 + log4 = -log [OH-]
[OH-] = 4 x 10^12