sebanyak 41gram CH3COONa dilarutkan dalam air sampai volumenha 250ml. jika Ar C=12, H=1, O=16, Na=23 dan tetapan hidrolisis (Kh) = 2 x 10-8 maka PH larutan gara

n = gr / Mr
n = 41 / (12 + 3 + 12 + 32 + 23)
n = 41 / 82
n = 0,5 mol

M = n / V
M = 0,5 / 0,25
M = 2 M

[OH-] = √Kh . n . M
[OH-] = √2 x 10^-8 . 1 . 2
[OH-] = √4 x 10^-8
[OH-] = 2 x 10^-4

pOH = -log[OH-]
pOH = -log 2 x 10^-4
pOH = 4 - log2

pH = 14 - (4 - log2)
pH = 14 - 4 + log2
pH = 10 + log2