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Bab Logaritma
Matematika SMA Kelas XI

²log a - 2 ( ²log b) = 2
²log a - ²log b² = 2
²log (a/b²) = 2
a/b² = 2²
a/b² = 4
a = 4 . b²

²log b - 2 (²log a) = -1
²log b - ²log a² = -1
²log (b/a²) = -1
b/a² = 2⁻¹
b = a²/2
a = √(b/2)

a = a
4 . b² = √(b/2)
16 . b⁴ = b/2
b⁴/b = 2/16
b³ = 1/8
b = ∛(1/8)
b = 1/2

a = 4 . b²
a = 4 . (1/2)²
a = 1

a . b = 1 . 1/2 = 1/2

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