larutan garam NH4Cl 0,1 M mengalamivhidrolisis menurut reaksi berikut. NH4 + H2O = NH4OH + H jika Kn = 10-9,maka ph larutan garam adalag...a.4 b.5 c.6 d.8 d.9

pKb = -logKb
pKb = -10^-9
pKb = 9

pH = 1/2 (14 - pKb - log[G])
pH = 1/2 (14 - 9 - log10^-1)
pH = 1/2 (5 + 1)
pH = 1/2 (6)
pH = 3

→ Atau :
[H+] = √Kw . Kb . M
[H+] = √10^-14 / 10^-9 . 10^-1
[H+] = √10^-5 . 10^-1
[H+] = √10^-6
[H+] = 10^-3

pH = -log[H+]
pH = -log ^10^-3
pH = 3 - log1
pH = 3

[ Tidak ada di pilihan ]

→ Cat :
Jika Kb = 10^-5 .. Jawabannya 5 ..