hitunglah ph larutan 100ml NH4CL 0,1 M, jika kb NH3 = 1 x 10^-5 !
Kimia
xdchandra
Pertanyaan
hitunglah ph larutan 100ml NH4CL 0,1 M, jika kb NH3 = 1 x 10^-5 !
1 Jawaban
-
1. Jawaban Robinn
pKb = -logKb
pKb = -log10^-5
pKb = 5
pH = 1/2 (14 - pKb - log[G])
pH = 1/2 (14 - 5 - log10^-1)
pH = 1/2 (9 + 1)
pH = 1/2 (10)
pH = 10