Hai. Mohon beri pembahasannya ya :) Ada 3 soal. Terima Kasih...

1. α, β  di KD I
cos α = 3/5 --> sin α = 4/5
cos (α+β) = - 12/13 --> sin (α+β) =  5/13

cos (α+β) = cos α cos β - sin α sin β = -12/13
3/5 cos β - 4/5 sin β = -12/13 ...kalikan 65
39 cos β - 52 sin β = -60 ....(1)

sin (α+β)  = sinα cos β + cos α sin β = 5/13
4/5  cos β + 3/5 sin β = 5/13 ---> kalikan 65
52 cos β + 39 sin β  = 25 ...(2)
.
(1) dan (2) eliminasi
39 cos β  - 52 sin β  = -60 ...kalikan 52
52 cos β + 39 sin β = 25......kalikan 39
....

-52(52) sin β = -60(52)
39(39) sin β = 25(39)
.
-(52)²-(39)² sin β = -60(52) - (25)(39)
sin β = - 4095 / - 4.225 = 63/65

5)
f(x) = kx²
lim (p->0) f(x+ap) - f(x + bp)/ (cp)
lim(p->0) k { (x+ap)² - (x+bp)²} / p(c)
lim(p->0)  k {x²+ 2apx + a²p² - x² - 2bpx - b²p²} /p(c)
lim(p->0)  k{ 2apx - 2bpx + p²(a²-b²)} / p(c)
lim(p->0) k p {2x (a-b) +p(a²-b²) / p(c)
lim(p->0)  k {2x (a-b) + p(a²-b²) / (c)
p = 0
= k{2x(a-b)/ c
= k(a-b)x / c

6.
s(x) = ax + b
s(6) = 2017
s(2017) = 6
...........kurangkan
(6-2017) a = (2017 -6)
a = 2011/-2011
a = -1

b = 2017 - 6a
b = 2017 -6(-1) = 2023

s(x) = ax + b
s(x) = -x + 2023