berapakah: a)cosec (-570) b)cotan (-210)
Matematika
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Pertanyaan
berapakah:
a)cosec (-570)
b)cotan (-210)
a)cosec (-570)
b)cotan (-210)
1 Jawaban
-
1. Jawaban 18Navillera
a.
= - cosec 570
= - cosec (360+210)
= - cosec 210
= - cosec (180+30)
= - (- cosec 30)
= - (-2)
= 2
b.
= cotan (-210)
= - cotan (180+30)
= - cotan30
= - akar 3