tinggi 6 alas 20 yang atas 12

TRAPESIUM

BC^2 = 6^2 + (20-12)^2 = 36 + 64 = 100
BC = akar100
BC = 10 cm

Keliling = 20+10+12+6 = 48 cm

sisimiring trapesium
= akar (20-12)² + 6²
= akar 100 = 10 cm

maka keliling trapesium
= 6 +20 + 12 + 10
=48cm