Matematika

Pertanyaan

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tolong dijawab ya buat latihan UKK!

1 Jawaban

  • 16.
    sin A= 3/5
    cos A = 4/5
    tan A = 3/4

    sinB= 12/13
    cos B = 5/12
    tan B = 12/5

    sin A. tanB  - tan A sin B =
    = (3/5)(12/5) - (3/4)(12/13)
    = (36/25) - (36/52)
    = 243/325

    17. Buktikan
    (1-sin² A)(1+ tan² A)  = 1
    = (cos² A)(1 + sin² A/cos² A)
    = cos²A + sin² A
     = 1

    18. lim(x->0)  (2x)/ √{(4+3x) - √(4-3x)}=
    = 2x {√(4+3x) + √(4-3x)} / {(4+3x-4 +3x)}
    = 2x {√(4 +3x) + √(4-3x)}/ (6x)
    = 1/3 {√(4+2x) + √(4-3x)}
    x = 0
    = 1/3 (√4 +√4)
    = 1/3 (4)
    = 4/3
    ...