jika titik A(4,2,q) B(2,-1,1) dan titik C(8,p+2,-8)segaris, nilai p+q

Dik :
A (4,2,q) , B (2,-2,1) dan C (8,p+2,-8) segaris
Dit : nilai p + q ?
AB = b - a
| 2 | | 4 | | -2 |
| -2 | _ | 2 | = | -4 |
| 1 | | q | | 1-q |
BC = c - b segaris..
| 8 | | 2 | | 6 | | -2 |
| p+2 | _ | -2 | = | p+4 | = -3 | p+4÷-3 | 
| -8 | | 1 | | -9 | | 3 | 
AB = BC
| -2 | | -2 |
| -4 | = | p+4÷-3 |
| 1-q | | 3 |

1-q = 3
q = -2

-4 = p+4÷ -3
12 = p+4
p = 12-4 = 8

jadi, nilai p+q = 8+(-2) = 6