Tentukan ph larutan (NH4) 2SO4 0,05M KbNH3 = 1,8 x10-5

(NH4)2SO4 -> NH4 + SO4
NH4 + H2O -> NH4OH + H

H+ = √Kw/Kb . [Garam]
= √10^-14/ 18x10^-6 . 5x10^-2
= √0,278 x 10^-10
= 0,52 x 10^-5
= 5,2 x 10^-6
pH = - log [H+]
= - log 5.2 x 10^-6
pH = 6- log 5,2