Tentukan ph larutan (NH4) 2SO4 0,05M KbNH3 = 1,8 x10-5

(NH4)2SO4
Diketahui : M larutan = 0,05 M
Kb NH3 = 1,8 x 10^-5

Apabila diketahui kb maka dicari [OH-]
[OH-] = akar kb.Mb
= akar 1,8 x 10^-5 x 5 x 10^-2
= akar 9 x 10^-7
= 3 x 10^-3,5
pOH = 3,5 - log 3
pH = 14-(3,5-log 3)
pH = 10,5+log 3