F(x)= (x^2-7)^2 (x^3+1)^2 berapakah f'(x)

u = (x² - 7)² → u' = 2(x² - 7)(2x) = 4x(x² - 7)
v = (x³ + 1)² → v' = 2(x³ + 1)(3x²) = 6x²(x³ + 1)
f'(x) = u'v + v'u
= 4x(x² - 7)(x³ + 1)² + 6x²(x³ + 1)(x² - 7)²
tinggal sederhanakan sesuai yg diminta