Matematika

Pertanyaan

diketahui cos (x-y)=3/4 dan sinx.siny=3/10 nilai tan x. tan y =

1 Jawaban

  • cos(x-y) = 3/4
    cosx.cosy + sinx.siny = 3/4
    cosx.cosy = 3/4 - sinx.siny
    =3/4 - 3/10
    = 15/20 - 6/20
    = 9/20

    tanx.tany = (sinx.siny)/(cosx.cosy)
    = (3/10) / (9/20)
    = 3/10 × 20/9
    = 2/3

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