poin gede, berapa luas ABCD

panjang DC =
DC/(6+8) = 12/8
DC/14 = 12/8
DC x 8 = 14 x 12
DC x 8 = 168
DC = 168 : 8 = 21

panjang AB
= DC/AB = 12/16
= 21/16+x = 12/16
(16 + x) x 12 = 21 x 16
= 192 + 12x = 336
12 x = 336 - 192
12 x = 144
x = 144 : 12
x = 12

AB = 16 + x = 16 + 12 = 28

luas = (jss x t) : 2
        = ((21 + 28) x 14):2
        = (49 x 14 ) : 2
        = 343 cm²