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Pertanyaan

Jika harga ta ch3cooh=10pangkat -5 tentukan ph lanjutan ch3cook 0,01m

1 Jawaban

  • pH = 1/2 (14 + pKa + log[G])
    pH = 1/2 (14 + (-log10^-5) + log10^-2)
    pH = 1/2 (14 + 5 - 2)
    pH = 1/2 (17)
    pH = 8,5

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