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Pertanyaan

tentukan konsentrasi ion H dan OH dalam larutan 0,15M (CH3COO)2Ca (Ka=1,5×10 pangkat -5

1 Jawaban

  • [OH-] = √Kw / Ka . n . M
    [OH-] = √10^-14 / 15 x 10^-6 . 2 . 15 x 10^-2
    [OH-] = √10^-8 . 10^-2 x 2
    [OH-] = √10^-10 x 2
    [OH-] = √2 x 10^-5

    pOH = 5 - log√2

    pH = 9 + log√2
    pH = 10 - log7

    [H+] = 7 x 10^-10

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