berapa pH larutan H2SO4 0,002 M (diketahui log 2 =0,301)?

H+ = v as x Ma
H+ = 2 x 2.10^-3
H+ = 4.10^-3
pH = - log H+
pH = - log 2^2 x 10^-5
pH = 5 - 2xlog2
pH = 5 - 2(0.301)
pH = 5- 0.602
pH = 4.398