Diketahui : F(x) = 2x+1/x-3 ditanya : F`(x)....? F`(x+1).....? F`(2)....?

Langsung aja y

f(x) = 2x+1 / x-3
y = 2x+1 / x-3
y(x-3) = 2x+1
xy - 3y = 2x + 1
xy - 2x = 3y + 1
x(y-2) = 3y+1
x = 3y+1 / y-2

f`¹(x) = (3x+1) / (x-2)

f`¹(x+1) = 3(x+1)+1 / x+1-2
f`¹(x+1) = 3x+3+1 / x-1
f`¹(x+1) = 3x+4 / x-1

f`¹(2) = 3.2 + 1 / (2-2)
f`¹(2) = 7/0
f`¹(x) = ∞

Semoga berguna +_+