Matematika

Pertanyaan

tolong bantu saya no.5.
tolong bantu saya no.5.

1 Jawaban

  • RQ = 40 cm
    SP = 7 cm
    RS = 24 cm
    PQ = 25 cm

    A.Luas Δ PQR
    L = √s(s-a)(s-b)(s-c)
       = √45(45 -25)(45-25)(45-40)
       = √45 × 20 × 20 × 5
       = √225  × 20 × 20
       = √225 × 400
       = √90000
       = 300 cm²
    s = 1/2 keliling

    B.Luas Δ PRS
    L =  1/2 (a×t)
       = 1/2 ( 7×24)
       = 1/2 × 168
       = 84 cm²

    C.Panjang PT
    T = L ÷ (A × 1/2 )
       = 300 cm ÷ (40 × 1/2)
       = 300 cm ÷ 20 cm
       = 15 cm