tolong bantu saya no.5.
Matematika
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Pertanyaan
tolong bantu saya no.5.
1 Jawaban
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1. Jawaban TantoFebrian
RQ = 40 cm
SP = 7 cm
RS = 24 cm
PQ = 25 cm
A.Luas Δ PQR
L = √s(s-a)(s-b)(s-c)
= √45(45 -25)(45-25)(45-40)
= √45 × 20 × 20 × 5
= √225 × 20 × 20
= √225 × 400
= √90000
= 300 cm²
s = 1/2 keliling
B.Luas Δ PRS
L = 1/2 (a×t)
= 1/2 ( 7×24)
= 1/2 × 168
= 84 cm²
C.Panjang PT
T = L ÷ (A × 1/2 )
= 300 cm ÷ (40 × 1/2)
= 300 cm ÷ 20 cm
= 15 cm