Jila panjang AC =24 cm AD= 13cm dan AB =20 cm luas layang layang adalah

Mencari panjang AO
AO = ½AC(d1)
AO = ½ . 24
AO = 12 cm

Cari panjang BO
BO = √AB^2 – AN^2
BO = √13^2 – 12^2
BO = √169 – 144
BO = √25
BO = 5 cm

Cari panjang DO

DO = √AD^2 – AN^2
DO = √20^2 – 12^2
DO = √400 – 144
DO = √256
DO = 16 cm


Panjang diagonal BD (d2)

BD = BO + DO
BD = 5 + 16
BD = 21 cm
maka,

L = ½ x d1 . d2
L = ½ x 24 x 21
L = 252 cm2