Gradien garis singgung kurva Y=X3-16x2+18x+3 dititik (1,6)

m=3.x^2 -32x+18
=3.(1)^2-32(1)+18
= -11

y'=m
3x^2-32x+18 = m
3(1)^2 - 32(1) + 18 = m
3-32+18 = m
-11 = m
inshaallah :)