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tentukan campuran larutan yang mmbentuk larutan penyangga
50 mL CH3COOH 0,1 M dengan 50 mL NaOH 0,1 M

1 Jawaban

  • CH3COOH + NaOH → CH3COONa + H2O

    → CH3COOH
    m = 50 x 0,1 = 5 mmol
    r = 5 mmol
    s = -

    → NaOH
    m = 50 x 0,1 = 5 mmol
    r = 5 mmol
    s = -

    → CH3COONa
    m = -
    r = 5 mmol
    s = 5 mmol

    M = 5 mmol / (50 + 50)
    M = 5 / 100
    M = 0,05

    → H2O
    m = -
    r = 5 mmol
    s = 5 mmol

    [OH-] = √Kw / Ka . M
    [OH-] = √10^-14 / 10^-5 . 5 x 10^-2
    [OH-] = √10^-9 . 5 x 10^-2
    [OH-] = √10^-11 x 5
    [OH-] = √10^-10 x 0,5
    [OH-] = √0,5 x 10^-5

    pOH = -log [OH-]
    pOH = -log √0,5 x 10^-5
    pOH = 5 - log√0,5

    pH = 14 - (5 - log√0,5)
    pH = 14 - 5 + log√0,5
    pH = 9 + log√0,5
    pH = 9 + (-0,15)
    pH = 9 - 0,15
    pH = 8,85

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