segitiga ABC diketahui unsur unsurnya a=24, b=15, dan c=20.tentukan sinus sudut B

a = 24 cm
b = 15 cm
c = 20 cm

s = ½(24 + 15 + 20)
s = ½(59)
s = 29,5

L = √s(s - a)(s - b)(s - c)
L = √29,5(29,5 - 24)(29,5 - 15)(29,5 - 20)
L = √29,5 × 5,5 × 14,5 × 9,5
L = √22.350
L = 149,5 cm²

L = ½ × a × c × sinB
149,5 = ½ × 24 × 20 × sinB
149,5 = 240 × sinB
0,6229 = sinB